110+3x^2+2=180

Solution for 110+3x^2+2=180 equation:

110+3x^2+2=180

We move all terms to the left:

110+3x^2+2-(180)=0

We add all the numbers together, and all the variables

3x^2-68=0

a = 3; b = 0; c = -68;
Δ = b2-4ac
Δ = 02-4·3·(-68)
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{51}}{2*3}=\frac{0-4\sqrt{51}}{6}
=-\frac{4\sqrt{51}}{6}
=-\frac{2\sqrt{51}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{51}}{2*3}=\frac{0+4\sqrt{51}}{6}
=\frac{4\sqrt{51}}{6}
=\frac{2\sqrt{51}}{3}
$